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Question

Find the value of k for which (cosx+sinx)2+ksinxcosx1=0 is an identity.

A
1
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B
2
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C
0
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D
1
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Solution

The correct option is B 2
If identity it should holds for all x.
so we put x=π4
We get
(12+12)2+k12121=0
and get k=2

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