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Question

Find the value of k for which each of the following system of linear equations has an infinite number of solutions:
k-3x+3y=k, kx+ky=12.

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Solution

The given system of equations can be written as
k-3x+3y-k=0 .....ikx+ky-12=0 .....ii
This system is of the form
a1x+b1y+c1=0a2x+b2y+c2=0
where a1=k-3, b1=3, c1=-k and a2=k, b2=k, c2=-12
For the given system of linear equations to have an infinite number of solutions
, we must have
a1a2=b1b2=c1c2k-3k=3k=-k-12k-3k=3k and 3k=-k-12k-3=3 and k2=36
k=6 and k=±6k=6
Hence, k = 6.

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