Question

Find the value of $k$ for which $k,2k-1$ and $2k+1$ are in $A.P$.

Answer 1

Given,

$k,2k-1$ and $2k+1$ are in A.P.

$\Rightarrow 2k-1-k=2k+1-2k+1$

$k-1=2$

$\therefore k=3$

Hence, this is the answer.