Question

Find the value of $k$, for which one root of the quadratic equation $k{x}^2-14x+8=0$ is $2.$

Answer 1

Given, root of the quadratic equation $k{x}^2-14x+8=0$ is $2$

Let us substitute the value of $x$ as $2$

$\Rightarrow k(2{)}^2-14\times 2+8=0$

$\Rightarrow$ $k\times 4=-8+28$

$\Rightarrow$ $k\times 4=20$

$\Rightarrow$ $k=\frac{20}{4}$

$\Rightarrow$ $k=5$