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Question

Find the value of k for which the equation 2x2kx+3=0 will have two real and equal roots.

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Solution

Given the equation is 2x2kx+3=0.

The discriminant of this equation =b24ac=(k)24×2.×3=k224.

Since the roots of the quadratic equation are all real and equal then the discriminant will be zero.

Then we've,

k224=0

or, k2=24

or, k=±26.

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