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Quadratic Equations

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Question

Find the value of $k$ for which the given value is a solution of the given equation $(x + 3) (2 x - 3 k) = 0; x = 6$

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Solution

Given equation is $(x + 3) (2 x - 3 k) = 0$
Substituting $x = 6$ , we get
$9 (12 - 3 k) = 0$
$\Rightarrow 12 = 3 k$
$\Rightarrow k = \frac{12}{3} = 4$

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