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Question

Find the value of k for which the lines kx - 5y + 4 = 0 and 5x - 2y + 5 = 0 are perpendicular to each other

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Solution

kx - 5y + 4 = 0

5 y equals k x plus 4 y equals k over 5 x plus 4 over 5

Slope of this line = m1 =k over 5

5x - 2y + 5 = 0

2 y equals 5 x plus 5 y equals 5 over 2 x plus 5 over 2

Slope of this line = m2 =5 over 2

Since, the lines are perpendicular, m1cross timesm2 = -1

k over 5 cross times fraction numerator begin display style 5 end style over denominator begin display style 2 end style end fraction equals negative 1 k equals negative 2


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Equation of Line perpendicular to a given Line
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