Question

Find the value of 'k' for which the pair of equations $2x-ky+3=0$, $4x+6y-5=0$ represent parallel lines.

Answer 1

$2x-ky+3=04x+6y-5=0$

To represent parallel lines,

$\frac{2}{4}=\frac{-k}{6}⟹\frac{1}{2}=\frac{-k}{6}⟹-k=\frac{6}{2}=-3$

$\therefore k=-3$