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Question
Find the value of k, for which the quadratic equation 2x2+kx+3=0 has two real equal roots.
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Solution
Given,
2x^2+Kx+3
here it is in the form ax^2+bc+C=0
here a=2, b=K, c=3
if it has two equal roots. then ∆=0
b^2-4ac=0
k^2-4(2)(3)=0
k^2-24=0
k^2=24
k=√24
k=+2√6 or -2√6
2x^2+Kx+3
here it is in the form ax^2+bc+C=0
here a=2, b=K, c=3
if it has two equal roots. then ∆=0
b^2-4ac=0
k^2-4(2)(3)=0
k^2-24=0
k^2=24
k=√24
k=+2√6 or -2√6
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