Find the value of k for which the roots of the equation $k x^{2} + 4 x + 1 = 0$ are real and equal.

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Solution

The correct option is C 4
Given a quadratic equation $a x^{2} + b x + c = 0$ , its discriminant is $b^{2} - 4 a c$ .
If its roots are real and equal, then $b^{2} - 4 a c = 0$ .
Thus, for the given equation,
$4^{2} - 4 k = 0$
$\Rightarrow k = 4$

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