Find the value of k for which the system: kx + 2y = 5, 3x + y = 1 has a unique solution
A
k=6
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B
k≠9
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C
k≠6
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D
k=6
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E
None of these
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Solution
The correct option is Ck≠6 We have, kx + 2y = 5 ...... (1) 3x + y = 1 ...... (2) Here, a1=k,b1=2,c1=5 a2=3,b2=1,c2=1 The given system of equations will have a unique solution if a1a2≠b1b2 i.e., if, k3≠21 i.e., if k3≠2 i.e., if k≠6