Find the value of k, if −4k2−(−11)2=3k2−9.
A
4i
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B
−4i
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C
4i
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D
−4i
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Solution
The correct options are C4i D−4i −4k2−(−11)2=3k2−9 −4k2−121=3k2−9 −4k2−3k2=121−9 −7k2=112 −k2=1127 −k2=16 Taking square roots on both the sides we get,