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Question

Find the value of k, if −4k2−(−11)2=3k2−9.

A
4i
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B
4i
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C
4i
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D
4i
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Solution

The correct options are
C 4i
D 4i
4k2(11)2=3k29
4k2121=3k29
4k23k2=1219
7k2=112
k2=1127
k2=16
Taking square roots on both the sides we get,
k=4i
k=4i

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