Question

Find the value of $k$ , if one of the zero of equation $6x^2-x-k=0$ is $\frac{3}{2}$.

Answer 1

$zero=\frac{3}{2}$

$f\left(x\right)=6x^2-x-k=0$

$f\left(\frac{3}{2}\right)=6\times \frac{3}{2}\times \frac{3}{2}-\frac{3}{2}-k=0$

$\frac{27}{2}-\frac{3}{2}=k$

$\frac{27-3}{2}=\frac{24}{2}=k$

$k=12$