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Question

Find the value of 'k' if the expression (4k)x2+2(k+2)x+5k+1 is a perfect square


A

0

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B

1

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C

2

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D

3

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Solution

The correct options are
A

0


D

3


Discriminant = 0
(2(k+2))24(8k+1)(4k)=0
4[(k2+4k+4)(32k+48k2k)]=0
k2+4k+432k4+8k2+k)]=0
9k227k=0
k=0 or k=3


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