Question

Find the value of k if the points $A(2,3),B(4,k)$ and $C(6,-3)$ are collinear.

Answer 1

Since $A,B\&C$ are colinear.

Slope of $AB$ is equal to the slope of $AC$.

$\frac{k-3}{4-2}=\frac{-3-3}{6-2}$

$k=0$