Find the value of k- if x -1 is a factor of p x -2 x 2- kx -2A- k -2B- k -2-2C- k -2-2D- k -2

The correct option is C k = −2 − √(2) p(x) = 2x^2 + kx + √(2) p(1) = 0. p(1) = 2(1)^2 + k(1) + √(2) = 0 2 + k + √(2) = 0 k = −2 − √(2) ...

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Standard IX

Mathematics

Factor Theorem

Find the valu...

Question

Find the value of k, if (x −1) is a factor of $p (x) = {2 x}^{2} + k x + \sqrt{2}$

$k = - 2$

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$k = 2$

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$k = - 2 - \sqrt{2}$

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$k = - 2 + \sqrt{2}$

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Solution

The correct option is C
$k = - 2 - \sqrt{2}$

$p (x) = {2 x}^{2} + k x + \sqrt{2}$

$p (1) = 0$ .

$p (1) = {2 (1)}^{2} + k (1) + \sqrt{2} = 0$

$2 + k + \sqrt{2} = 0$

$k = - 2 - \sqrt{2}$

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Similar questions

Find the value of k, if (x −1) is a factor of p(x) in the following case:
$p (x) = {2 x}^{2} + k x + \sqrt{2}$

Q. Find the value of

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in each of the following cases:
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p (x) = x^{2} + x + k

(ii)

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(iv)

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p (x) = {2 x}^{2} + k x + \sqrt{2}

Find the value of k, if (x −1) is a factor of p(x) in each of the following cases:
$(i) p (x) = x^{2} + x + k$
$(i i) p (x) = {2 x}^{2} + k x + \sqrt{2}$ [4 MARKS]

Q. If (x + 1) is a factor of (2x² + kx), then k = ?
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Find the value of k, if (x −1) is a factor of p(x)=2x2+kx+√2

The correct option is C k=−2−√2 p(x)=2x2+kx+√2 p(1)=0. p(1)=2(1)2+k(1)+√2=0 2+k+√2=0 k=−2−√2

Find the value of k, if (x −1) is a factor of $p (x) = {2 x}^{2} + k x + \sqrt{2}$

The correct option is C
$k = - 2 - \sqrt{2}$

$p (x) = {2 x}^{2} + k x + \sqrt{2}$

$p (1) = 0$ .

$p (1) = {2 (1)}^{2} + k (1) + \sqrt{2} = 0$

$2 + k + \sqrt{2} = 0$

$k = - 2 - \sqrt{2}$