Find the value of ‘k’ if x−1 is a factor of P(x) = 4x3 + x2–3x+k.
-1
-2
-3
-4
Since x-1 is the factor of 4x3 + x2 – 3x + k, therefore at x = 1,
P(x) = 0
So 4(1)3 + (1)2 – 3(1) + k = 0
i.e, 2 + k=0
and k = -2
Find the value of k if x – 3 is the factor of P(x) = x2–2x−k.
Find the value of k, if x − 1 is a factor of p(x) in each of the following cases:
(i) p(x) = x2 + x + k (ii)
(iii) (iv) p(x) = kx2 − 3x + k