Question

Find the value of $k$, if $(x-1)$ is a factor of $p\left(x\right)=4x^3+x^2–3x+k$.

• A. $-1$
• B. $-2$
• C. $-3$
• D. $-4$

Answer 1

The correct option is B $-2$

$(x-1)$ is the factor of $p\left(x\right)$
Using factor theorem,
$p\left(1\right)=0$
$4\times 1^3+{\left(1\right)}^2–3\times 1+k=0$
$4+1-3+k=0$
$k=-2$