Find the value of $k$ , if $x - 1$ is a factor of $p (x)$ in each of the following cases
$p (x) = x^{3} + x + k$

Open in App

Solution

If $(x - 1)$ is a factor of $p (x)$
Then $p (1)$ should be zero.
$p (x) = x^{3} + x + k$
$p (1) = 1 + 1 + k = 0$
$= 2 + k = 0$
$k = - 2$ .

Suggest Corrections

Similar questions

Q. Find the value of

k

, if

x - 1

is a factor of

p (x)

in the following cases:

p (x) = k x^{2} - 3 x + k

Q. Find the value of

k

, if

x - 1

is a factor of

p (x)

in the following case:

p (x) = k x^{2} - \sqrt{2} x + 1

Q. If

(x - 3)

is a factor of

p (x)

, find the value of

k

, Where

p (x) =

x^{2} - k^{2} x + k

Find the value of k, if x − 1 is a factor of p(x) in each of the following cases:

(i) p(x) = x² + x + k (ii)

(iii) (iv) p(x) = kx² − 3x + k

Find the value of k, if (x −1) is a factor of p(x) in each of the following cases:
$(i) p (x) = x^{2} + x + k$
$(i i) p (x) = {2 x}^{2} + k x + \sqrt{2}$ [4 MARKS]

Join BYJU'S Learning Program

Find the value of k, if x−1 is a factor of p(x) in each of the following cases p(x)=x3+x+k

If (x−1) is a factor of p(x)Then p(1) should be zero.p(x)=x3+x+kp(1)=1+1+k=0=2+k=0k=−2.

Find the value of $k$ , if $x - 1$ is a factor of $p (x)$ in each of the following cases
$p (x) = x^{3} + x + k$

If $(x - 1)$ is a factor of $p (x)$
Then $p (1)$ should be zero.
$p (x) = x^{3} + x + k$
$p (1) = 1 + 1 + k = 0$
$= 2 + k = 0$
$k = - 2$ .