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Question

Find the value of k, if x - 1 is a factor of p(x)
p(x)=kx23x+k

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Solution

(x -1) is a factor, so we substitute x = 1 in each case and solve for k by making p(1) equal to 0.
p(x)=kx23x+kp(1)=k3+k=02k3=0k=32

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