Find the value of $k$ , if $x = 2$ is a zero of $p (x) = x^{2} + k x + 2 k$

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Solution

Hence, $P (2) = 0$
4+2k+2k =0
4k+4 =0
$k = - 1$

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Find the value of k, if x=2 is a zero of p(x)=x2+kx+2k

Hence, P(2)=04+2k+2k =04k+4 =0k=−1

Find the value of $k$ , if $x = 2$ is a zero of $p (x) = x^{2} + k x + 2 k$

Hence, $P (2) = 0$
4+2k+2k =0
4k+4 =0
$k = - 1$