Find the value ofk, if x=2,y=1 is a solution to the equation 2x+3y=k.
The given condition x=2and y=1is the solution of the equation 2x+3y=k.
On substituting the values of xandy in the equation 2x+3y=k, we get,
2x+3y=k⇒(2×2)+(3×1)=k⇒4+3=k⇒k=7Hence, the required value of k is 7.
Find the value of k if x=2,y=1 is a solution, of the equation 2x+3y=k.
Find the value of k, if x=2,y=1 is a solution of the equation 2x+3y=k. Find two more solutions of the resultant equation.
If x= 2 and y= 3 is a solution of 2x - 3y+ k = 0 find k value and write the resultant equation