Find the value of k if x=3 and y=2 is a solution of the equation 5x+3y−k=0.
A
k=21
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B
k=12
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C
k=19
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D
k=26
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Solution
The correct option is Ak=21 Given, equation is: 5x+3y−k=0 Putting value of x=3 and y=2 in the above equation, we get 5(3)+3(2)−k=0 or, 15+6−k=0 or, 21−k=0 or, k=21