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Question

Find the value of k if x=3 and y=2 is a solution of the equation 5x+3yk=0.

A
k=21
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B
k=12
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C
k=19
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D
k=26
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Solution

The correct option is A k=21
Given, equation is: 5x+3yk=0
Putting value of x=3 and y=2 in the above equation, we get
5(3)+3(2)k=0
or, 15+6k=0
or, 21k=0
or, k=21

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