Consider given the expression ,
k2x3−kx2+3kx−k
Also given that,
x−3or x−3=0⇒x=3 is factor of k2x3−kx2+3kx−k
So,
k233−k.32+3k3−k=0
27k2−9k+9k−k=0
27k2−k=0
k(27k−1)=0
k=0or27k−1=0
k=0ork=127
Hence, this is the answer.
Find the value k where x-3id a factor of k2x3-kx2+3kx-k.
find the value of k if (x-1) is a factor of the polynomial kx2-3x+k
Find the value of k, if x - 1 is a factor p(x) in each of the following cases: (i) p(x)=x2+x+k (ii) p(x)=2x2+kx+√2 (iii) p(x)=kx2−√2x+1 (iv) p(x)=kx2−3x+k