wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the value of k if x-3 is a factor of k2x3-kx2+3kx-k.

Open in App
Solution

Equate the equation to zero.
hence,
k2x3-kx2+3kx-k=0
(x-3) is factor. That means, (x-3) = 0. Hence , x=3 must satisfy the equation. Substituting 3 instead of x in equation,

k^2 * 27 - k*9 + 3k*3 -k =0

27k^2 - 9k + 9k -k =0
27k^2 - k =0
27k^2 = k
27k = 1 ( cancel k on both sides)
k = 1/27.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factor Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon