Find the value of k, so that (2,1) is the midpoint between (1,k) and (3,1).
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is A1 We know the midpoint of the line joining the points (x1,y1) and (x2,y2)is given as (x1+x22,y1+y22) Substitute the values, we get (1+32,k+12)=(2,1) On equating, we get (k+12)=1 ⇒k+1=2 ⇒k=2−1 ⇒k=1