Question

Find the value of K so that sum of the roots of the equations $3x^2+(2x-11)xK-5=0$ is equal to the product of the roots.

• A. $4$
• B. $-4$
• C. $\frac{-5}{11}$
• D. $-\frac{1}{4}$

Answer 1

The correct option is C $\frac{-5}{11}$

Rewriting the equation, $\Rightarrow x^2(3+2K)-x\left(11K\right)-5=0$

Given $-b/a=c/a$ $\Rightarrow -b=c$

$\to 11K=-5$

$\therefore K=\frac{-5}{11}$