Question

Find the value of k that the quadratic equation

x² - 2kx+(7k-12)=0

Answer 1

b^2=4 ac

(-2k)^2 = 4 .1.(7k -12)

4 k^2 = 4(7k-12)

k ^2 = 7k -12

k ^2- 7k +12=0

k^2 -4k -3k +12=0

k (k -4)-3(k-4)=0

(k-4)(k-3)=0

ie k=3,4 ans

hope it helps