Question 63

Find the value of k, where 31k2 is divisible by 6.

Open in App

Solution

Given, 31k2 is divisible by 6. Then, it is also divisible by 2 and 3 both.
Now, 31k2 is divisible by 3, sum of its digits is a multiple of 3.
i.e. 3 + 1 + k + 2 = 0, 3, 6, 9, 12, .....
$\Rightarrow$ k + 6 = 0, 3, 6, 9, 12
$\Rightarrow$ k = 0 or 3, 6, 9

Suggest Corrections

Similar questions

Question 64

1y3y6 is divisible by 11. Find the value of y.

42 \times 57 \times 92 \times 91 \times 52 \times 62 \times 63 \times 64 \times 65 \times 66 \times 67

42^{n}

Question 73

If 123123A4 is divisible by 11, find the value of A.

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program