Find the value of λ if the point (3, 5) lies inside the circle x2+y2+6x+λy+5=0
λ< 5
λ<-57/5
λ>5
λ<11
If (3, 5) lies inside the circle, then S1 will be less than zero
S1≡32+52+3×6+5λ+5<0
⇒9+25+18+5λ+5<0
⇒5λ+57<0
⇒λ<−575
The point P(9, 12) lies inside the circle x2+y2−6x−8y−24=0