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Byju's Answer
Standard XII
Mathematics
Sum of Binomial Coefficients with Alternate Signs
Find the valu...
Question
Find the value of
(
a
+
√
a
2
−
1
)
7
+
(
a
−
√
a
2
−
1
)
7
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Solution
We have the sum of two expansions whose terms are numerically the same; but in the second expansion the second, fourth, sixth and eighth terms are negative, and therefore destroy corresponding terms of the first expansion.
∴
we get it equal to
=
2
[
a
7
+
21
a
5
(
a
2
−
1
)
+
35
a
3
(
a
2
−
1
)
2
+
7
a
(
a
2
−
1
)
3
]
=
2
a
(
64
a
6
−
112
a
4
+
56
a
2
−
7
)
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0
Similar questions
Q.
In an
A
.
P
.
if
a
2
+
a
5
−
a
3
=
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and
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=
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,
then the value of
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is
Q.
If
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=
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solve for
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Q.
If
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]
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so that
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Q.
If
A
=
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Q.
Given
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Standard XII Mathematics
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