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Question

Find the value of (a+a21)7+(aa21)7

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Solution

We have the sum of two expansions whose terms are numerically the same; but in the second expansion the second, fourth, sixth and eighth terms are negative, and therefore destroy corresponding terms of the first expansion.
we get it equal to
=2[a7+21a5(a21)+35a3(a21)2+7a(a21)3]
=2a(64a6112a4+56a27)

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