Find the value of- -15-2 - 13-3 - 12-4 -

The correct option is D 68 [15^ 2 + 13^ 3 + 12^ 4 ] = 5^2 + 3^3 + 2^4 = 25 + 27 + 16 = 68 So, option C is correct. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Exponents with like Bases

Find the valu...

Question

Find the value of: $[\frac{1}{5^{- 2}} + \frac{1}{3^{- 3}} + \frac{1}{2^{- 4}}]$

- \frac{1}{68}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{68}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

68

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 68

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $68$
$[\frac{1}{5^{- 2}} + \frac{1}{3^{- 3}} + \frac{1}{2^{- 4}}] = 5^{2} + 3^{3} + 2^{4}$

$= 25 + 27 + 16$
$= 68$

So, option $C$ is correct.

Suggest Corrections

Similar questions

What is the value of $x$ when $5 \frac{1}{2} : x :: 8 \frac{1}{2} : \frac{1}{4}$ ?

Compute the following:
$(i i i) ⎡ ⎢ ⎣ \begin{matrix} - 1 & 4 & - 6 8 & 5 & 16 2 & 8 & 5 \end{matrix} ⎤ ⎥ ⎦ + ⎡ ⎢ ⎣ \begin{matrix} 12 & 7 & 6 8 & 0 & 5 3 & 2 & 4 \end{matrix} ⎤ ⎥ ⎦$

Question 68

Solve the following:

$\frac{3 t + 5}{4} - 1 = \frac{4 t - 3}{5}$

Find the value of each of the following using the short-cut method:
1. $(25)^{3}$ 2. $(47)^{3}$ 3. $(68)^{3}$ 4. $(84)^{3}$

Using elementary transformations, find the inverse of the followng matrix.

$[\begin{matrix} 6 & - 3 - 2 & 1 \end{matrix}]$

Join BYJU'S Learning Program

Find the value of: [15−2+13−3+12−4]

The correct option is D 68[15−2+13−3+12−4]=52+33+24=25+27+16=68So, option C is correct.

Find the value of: $[\frac{1}{5^{- 2}} + \frac{1}{3^{- 3}} + \frac{1}{2^{- 4}}]$

The correct option is D $68$
$[\frac{1}{5^{- 2}} + \frac{1}{3^{- 3}} + \frac{1}{2^{- 4}}] = 5^{2} + 3^{3} + 2^{4}$

$= 25 + 27 + 16$
$= 68$

So, option $C$ is correct.