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Question

Find the value of [sin222o+sin268ocos222ocos268o+sin363o+cos63osin27o]

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Solution

[sin222+sin268cosec222cos268+sin263+cos63sin27]
[sin222+sin2(9022)cosec2(9068)cos268+sin263+cos63sin(9063)]
[sin222+cos222sec268cos268+sin263+cos63cos63]
1secθ=cosθ and sin2θ+cos2θ=1
[11+sin263+cos263]
1+1
=2


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