Question

Find the value of ${\left(\frac{9}{8}\right)}^{-3}\times {\left(\frac{8}{9}\right)}^{-2}$

Answer 1

$(\frac{9}{8}{)}^{-3}\times (\frac{8}{9}{)}^{-2}=(\frac{8}{9}{)}^3\times (\frac{9}{8}{)}^2=\left(\frac{8}{9}\right)\times \left(\frac{8}{9}\right)\times \left(\frac{8}{9}\right)\times \left(\frac{9}{8}\right)\times \left(\frac{9}{8}\right)=\left(\frac{8}{9}\right)$