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Question

Find the value of limx 0ax1x


A

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B

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C

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D

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Solution

The correct option is B


We have,limx 0ax1x

It is an examle of 00 form

While evaluating the limit,we can use expansion of ax.

We know,

ax=1+x(logea)+x22!(logea)2+......

substituting the expansion of ax in the numerator of the limit

=limx 0[1+x(logea)+x22!(logea)2+.......]1x

=limx 0logea+x2!(logea)2+......

=logea+0

=logea


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