Question

Find the value of $\underset{x\to 5}{lim}(x^2-5x+10)$

Answer 1

The given limit is a direct limit which can be found by substituting x=5.

$\Rightarrow$ $\underset{x\to 5}{lim}(x^2-5x+10)=5^2-5\times 5+10$

=10

We can directly substitute the value because the function $x^2-5x+10$ is defined at x=5 and the limiting

value is equal to the value of the function at x=5.