Question

Find the value of :$\underset{x\to 0}{lim}\frac{{\sin }^{2}x}{x^2}$

Answer 1

Now,

$\underset{x\to 0}{lim}\frac{{\sin }^{2}x}{x^2}$

$={\left(\underset{x\to 0}{lim}\frac{\sin x}{x}\right)}^2$

$=1^2$
$=1$.