Question

Find the value of ${\log }_{10}72+{\log }_{10}\frac{1}{8}$ using log table

• A. $0.903$
• B. $0.303$
• C. $0.954$
• D. $1.234$

Answer 1

Answer: (C)

$0.954$

${\log }_{10}72+{\log }_{10}\left(\frac{1}{8}\right)$

$={\log }_{10}(72\times \frac{1}{8})={\log }_{10}9={\log }_{10}{3}^2$

$=2.{\log }_{10}3=2\left(0.477\right)=0.954$