Find the value of ${log}_{2} 32$ .

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Solution

From question,

$l o g_{2} 32$

=> $l o g_{2} 2^{5}$

=> $5 l o g_{2}$ $2$

=> $5 \times 1$

=> $5$

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Similar questions

Find the value of ${log}_{2} . {log}_{3} 9$

{log}_{2 - \sqrt{3}} (2 + \sqrt{3}) = - x

x

\frac{{log}_{2} a}{4} = \frac{{log}_{2} b}{6} = \frac{{log}_{2} c}{3 p}

a^{2} b^{2} c = 1

- p = \frac{20}{m}

m

l o g_{2 \sqrt{3}} 1728

Find the value of ${log}_{2} . {log}_{3} 9$

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