log3 4.log4 5.log5 6.log6 7.log7 8.log8 9
Using change of base identity, logb a=logm alogm b and taking common base as 10, we get
log 4log 3.log 5log 4.log 6log 5.log 7log 6.log 8log 7.log 9log 8
=log 9log 3
=log 9log 3=log 32log 3=2×log 3log 3=2