Find the value of ${log}_{81} 3$

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Solution

Formula used
${log}_{a^{n}} b^{m} = \frac{m}{n} {log}_{a} b$
Now, ${log}_{81} 3 = {log}_{3^{4}} 3^{1}$
$= \frac{1}{4} {log}_{3} 3$
$= \frac{1}{4}$ $(∵ {log}_{a} a = 1)$

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