Find the value of log a + log b - log ab.

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Solution

log a + log b - log ab

= log ab - log ab

= 0

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Similar questions

2^{(\sqrt{l o g_{a} \sqrt[4]{a b} + l o g_{b} \sqrt[4]{a b}} - \sqrt{l o g_{a} \sqrt[4]{b / a} + l o g_{b} \sqrt[4]{a / b}}) . \sqrt{l o g_{a} b}}

= {\begin{matrix} 2, b \geq a \geq 1 2^{l o g_{a} b}, 1 < b < a \end{matrix}

[({log}_{b} a) ({log}_{c} b) ({log}_{a} c)]

{l o g}_{b} x \times {l o g}_{a} b =

log (a + b) = log a + log b

a

b

\frac{l o g (a b)}{l o g b} = \frac{3}{2}

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