Question

Find the value of $m$:

$(2^{-1}\times 4^{-1})+2^{-2}=\frac{3}{m}$

Answer 1

$\begin{array}{cc}LHS& =\left(2^{-1}\times 4^{-1}\right)+2^{-2}\\ & =\left(\frac{1}{2}\times \frac{1}{4}\right)+\frac{1}{2^2}\\ & =\frac{1}{8}+\frac{1}{4}\\ & =\frac{1+2}{8}\\ & =\frac{3}{8}\end{array}$

Now, we will equate $LHS$ and $RHS$ to find the value of $m,$

$\frac{3}{8}=\frac{3}{m}$

$\Rightarrow m=4$

Hence, the value of $m$ is equal to $8$.