Find the value of m and n the equation have infinitely many solutions:
$20 x + 12 y = m$ and $- 2 n x + 2 y = 10$

m = 60; n = \frac{- 5}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m = - 60; n = \frac{5}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m = 60; n = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m = \frac{- 5}{3}; n = 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $m = 60; n = \frac{- 5}{3}$
Given equation $20 x + 12 y = m, - 2 n x + 2 y = 10$
For infinity of solutions, $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$
$\frac{20}{- 2 n} = \frac{12}{2} = \frac{m}{10}$
$m = 60, n = \frac{- 5}{3}$

Suggest Corrections

Similar questions

If the pair of equations $2 x + 3 y = 11 and (m + n) x + (2 m - n) y = 33$ has infinitely many solutions, then

(a) m = −1, n = 5
(b) m = 1, n = 5
(c) m = 5, n = 1
(d) m = 1, n = −1

If 3m - 5m = -1 and 2m = n-3, find the value of (3m+5n) and (m+2n).

$\frac{5 + \sqrt{2}}{5 - \sqrt{2}} = m + n \sqrt{2}$

Find the value of m and n

Q. If m and n are the roots of the equation

x^{2} - 5 x + 3 = 0

then find the value of

(m + n)^{3} + 4 m n

If $3 m - 5 m = - 1$ and $2 m = n - 3$ find the value of $(3 m + 5 n)$ and $(m + 2 n)$ .

Join BYJU'S Learning Program

Find the value of m and n the equation have infinitely many solutions:20x+12y=m and −2nx+2y=10

The correct option is C m=60;n=−53Given equation 20x+12y=m,−2nx+2y=10For infinity of solutions, a1a2=b1b2=c1c220−2n=122=m10m=60,n=−53

Find the value of m and n the equation have infinitely many solutions:
$20 x + 12 y = m$ and $- 2 n x + 2 y = 10$

The correct option is C $m = 60; n = \frac{- 5}{3}$
Given equation $20 x + 12 y = m, - 2 n x + 2 y = 10$
For infinity of solutions, $\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$
$\frac{20}{- 2 n} = \frac{12}{2} = \frac{m}{10}$
$m = 60, n = \frac{- 5}{3}$