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Question

Find the value of m and n using elimination method:
7m+6n=−37 and 3m−2n=7

A
(1,5)
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B
(1,5)
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C
(1,5)
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D
(1,5)
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Solution

The correct option is D (1,5)
7m+6n=37
3m2n=7
Multiply equation (2) by 3 and then subtract the equation
7m+6n=37
9m6n=21
_____________
16m=16
m=1616
m=1
Put the value of m=1 in equation (2), we get
3m2n=7
3(1)2n=7
37=2n
10=2n
n=102
n=5
Therefore, the solution is (1,5).

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