Find the value of ‘m’ for which the given value of the variable is a solution of the equation x2+2ax+m=0; x+a=0
Step 1:- For, x2+2ax+m=0 at x+a=0,x=−a
(−a)2+2a(−a)+m=0
Step 2:- a2−2a2+m=0
Step 3:- m = a2
Find the value of ‘m’ for which the given value of the variable is a solution of the equation : 3x2+2mx–3=0;2x–1=0