Find the value of ‘m’ for which the given value of the variable is a solution of the equation :
$3 x^{2} + 2 m x - 3 = 0; 2 x - 1 = 0$

Open in App

Solution

For, \(3x^2 + 2mx – 3 = 0,

At 2x-1 =0,

$\Rightarrow$ x= $\frac{1}{2}$

$\Rightarrow$ $3 (\frac{1}{2})^{2} + 2 m (1 / 2) - 3 = 0$

$\Rightarrow$ $\frac{3}{4} + m - 3 = 0$

$\Rightarrow$ m= $\frac{9}{4}$

Suggest Corrections

Similar questions

Find the value of ‘m’ for which the given value of the variable is a solution of the equation $x^{2} + 2 a x + m = 0$ ; $x + a = 0$

m

3 x^{2} - 2 m x - 4 = 0

x^{2} - 4 m x + 2 = 0

k

3 x^{2} + 2 k x - 3 = 0, x = - \frac{1}{2}

For equation given below, find the value of 'm' so that the equation has equal roots. Also find the solution of equation:

(m-3)x² - 4x + 1 = 0

x = 2

x = 3

{3 x}^{2} - 2 m x - 2 n = 0

m

n

Join BYJU'S Learning Program