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B
50
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C
93
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D
103
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Solution
The correct option is C 93 ClassFrequencyMorethanIntervalcumulativefrequency0−310m3−61593−10=836−91883−15=689−122268−18=5012−151650−22=2815−181228−16=12 From the cumulative frequency distribution of more than type, the value of m is total frequency = 10 + 15 + 18 + 22 + 16 +12 = 93