Find the value of:
$(v) 2 p - 3 q + 4 r - 8 s$ , when $p = 10, q = 8, r = 6$ and $s = 2$

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Solution

On substituting $p = 10, q = 8, r = 6$ and $s = 2$ in $2 p - 3 q + 4 r - 8 s$ , we get
$2 p - 3 q + 4 r - 8 s = 2 \times 10 - 3 \times 8 + 4 \times 6 - 8 \times 2$
$= 20 - 24 + 24 - 16$
$= 4$
Therefore, the value of $2 p - 3 q + 4 r - 8 s = 4$

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