Question

Find the value of:
$\left(v\right)2p-3q+4r-8s$, when $p=10,q=8,r=6$ and $s=2$

Answer 1

On substituting $p=10,q=8,r=6$ and $s=2$ in $2p-3q+4r-8s$, we get
$2p-3q+4r-8s=2\times 10–3\times 8+4\times 6–8\times 2$
$=20–24+24–16$
$=4$
Therefore, the value of $2p-3q+4r-8s=4$